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About Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How works Test new features Press Copyright Contact us CreatorsN = 2c 1, for some integer c Step 2, specialization 4 (n = 2c 1) →(n2 = (2c 1)2) Laws of arithmetic 5 n2 = (2c 1)2 Steps 3 & 4, modus ponens = 4c2 4c 1 Laws of arithmetic = 2(2c2 2c) 1 Laws of arithmetic 6 ∃k (n2 = 2k 1) Step 5, generalization 7All Rights Reserved For more information on this site, please read our Privacy Policy, Terms of Service, and Ad Choices Privacy Policy, Terms of Service, and Ad
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